documentformat.openxml.variablereplacer
using (WordprocessingDocument document = WordprocessingDocument.Open(filePath, true)) { MainDocumentPart mainPart = document.MainDocumentPart; Dictionary<string, string> replacers = new Dictionary<string, string>(32); _openXmlVariableReplacer.ReplaceVariables(mainPart.Document, replacers); }
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over 8 years ago
0.1.0
over 8 years ago
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22,589 total
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| Registry | nuget.org |
| Source | Repository |
| JSON API | View JSON |
| CodeMeta | codemeta.json |
Package Details
Repository
| Stars | 7 on GitHub |
| Forks | 2 on GitHub |
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